Here comes the interesting all-time best playing XI of Mumbai Indians from Jasprit Bumrah. The man of the match for Mumbai Indians in the Indian Premier League 2019 final has picked the all-time best XI of Mumbai Indians. The flamboyant cricket has made quite a few interesting inclusions to his side.
In an interview with MITV, Jasprit Bumrah picked Rohit Sharma and Sachin Tendulkar will be opening the innings for his side. Without any surprise, Rohit Sharma will be leading the side.Ambati Rayudu to bat at number 3:
Coming to the number 3 position, he chose Ambati Rayudu, who played terrific knocks for the team during his playing days. Rayudu has always been their match-winner during the crunch moments of the game, however, they let him go when CSK opted to pick him in the auction.Sachin Tendulkar (Image Credit: Google)
Then comes Dinesh Karthik, who was picked as the wicketkeeper-batsman for the team. Karthik will be playing at number 4 for the team. He is followed by the all-rounder Hardik Pandya, who always played with passion for Mumbai Indians.
Then the Big West Indians Kieron Pollard, who always been there for the franchise. He played many scintillating knocks for the team over the years and helped them win many nerve-cracking matches.Photo Credit: BCCI/IPL.
Surprisingly, he opted for Krunal Pandya in the playing XI as well. Then comes the off-spinner Harbhajan Singh, who has been exceptional for the team over the years. He delivered many match-winning spells during his playing days for the team.
Coming to the fast bowling department, Jasprit Bumrah added his teacher-like man Lasith Malinga and then included himself in the playing XI. Then comes the fast bowler Mitchell Johnson, who was at his brutal best when playing for Mumbai Indians.
Rohit Sharma, Sachin Tendulkar, Ambati Rayudu, Dinesh Karthik (wk), Hardik Pandya, Kieron Pollard, Krunal Pandya, Harbhajan Singh, Lasith Malinga, Mitchell Johnson, Jasprit Bumrah.